$x\frac{d}{dx}+2x=3x^3y^{\frac{4}{3}}$
$\frac{3x}{2x-10y}$
$\frac{-80}{-20}$
$-5r+5r$
$\frac{2x^2}{4}-\frac{x}{6}=\frac{2}{3}$
$5x+2y-3x+8y+6$
$2x+5>=9$
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