$4x+3y=1$
$\frac{2}{5}\left(10\right)^x=40$
$5x^4-3x^2$
$\ln\left(1+x^3\right)+.5\ln\left(x\right)-\ln\left(\sin\left(x\right)\right)$
$8x^2-40x+17$
$\sqrt{5x+4}-2=6x-5$
$8x-\frac{\left(4-x\right)^{\frac{3}{2}}}{\frac{3}{2}}$
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