$\frac{dy}{dx}=\frac{9y^2}{x}$
$\frac{1}{cos\left(t\right)}$
$-0.75x^3+0x^2+9x-15$
$\frac{\sin\left(x\right)}{\sqrt{1-\sin^2\left(x\right)}}=\csc\left(x\right)$
$\left(3x+2y\right)z$
$\frac{x}{3}-2=9$
$8>3+\frac{t}{4}$
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