$99+4$
$50u-18u^3$
$\tan\left(36\right)\left(35-x\right)=\tan\left(50\right)\left(x\right)$
$6a\left(x+1\right)$
$\int5d\cdot$
$1-48$
$\frac{6.5-4}{9-4}$
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