$\left(3x^{2b}+5\right)\left(4x^{2b}-7\right)$
$\left(\frac{3}{2}a^2-\frac{5}{4}b^3\right)^2$
$x+y=49$
$-x+x+1$
$2\cos^2x-\cos2x-1=0$
$\left(5x^4-\:2\right)^2$
$y'=\left(x+y-2\right)^2$
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