$3-4\left(2^0-6^1+1^9\right)^2$
$\frac{x^2-4x}{3-x^2}$
$\frac{5+n}{3}=-2$
$4tan^2x=tanx$
$\frac{d}{dx}\left(5xy-1\right)$
$\frac { - x + 2 } { x - 3 } \leq 1$
$2^{\frac{3}{2}}\:x\:2^{\frac{1}{5}}$
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