$2y+6-y=1$
$t'=-k\left(t-22\right)$
$x\left(y-1\right)+y\left(1-x\right)$
$\left(x^3-6\right)\left(x^3+6\right)$
$( \frac { 0 + 4 } { 2 } ) ^ { 2 }$
$\sqrt[2]{4+\sqrt{15}}\cdot\sqrt{4-\sqrt{15}}$
$2+4y-7y^2+5y^2+5+4y-2y$
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