$\int\left(\frac{1}{x+10}\right)dx$
$\left(\frac{x}{y}-\frac{y}{x}\right)^4.\left(-2+x\right)^4$
$-24.37+5.19$
$\int_{-1}^0\frac{\left(4x^2-1\right)}{\left(x^3-4x^2+x+6\right)}dx$
$0,235+8,34$
$-u-10w$
$\int\frac{-1}{\left(y-2\right)}dx$
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