$\left(2^2\cdot3^3\right)\cdot\left(4^2\cdot2^3\right)$
$x^2+24xy+144y^2$
$36x^4-16$
$\frac{dy}{dx}=\left(\frac{\left(y-1\right)^2}{\left(x+1\right)^2}\right)$
$4x^2-\:2x<2$
$-758-\left(-132\right)$
$2x^5-4x^3+x-1$
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