$\left(m^3n^2-4\right)^3$
$\left(ku-3w\right)\left(ku+3w\right)$
$\left(2a\right)\left(-2^2\right)\left(-3a^3\right)\left(4a\right)$
$\left(n+1\right)^6-\left(n+1\right)^2$
$\sqrt[6]{\frac{1}{m^2}}\cdot\:\sqrt{\frac{1}{m}}$
$24\left(x-1\right)$
$\frac{20}{-2}$
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