$\frac{2x}{x+4}=6-\frac{8}{x+4}$
$-16\pi8\pi$
$\left(x-1\right)^2-\left(x-1\right)^2+12\ge0$
$-9b-4$
$\int\sin^5\left(7x\right)dx$
$\left(\sqrt[4]{b\cdot a^6}\right)^8$
$6m\left(3x-y\right)+9n\left(6x-2y\right)$
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