$\left(5a\:+\:4b\:-\:6c\right)-\left(3a\:+\:b\right)$
$x^4+0+9x^2+4x+12$
$\int\frac{r^2+8}{r^3+3r^2-4r}dt$
$\int_{-\infty}^{-2}\left(\frac{1}{x}\right)dx$
$\left(2a^8-5a^4\right)^2$
$x^2+10x+27<0$
$\left(2a-3\right)\left(a-2\right)$
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