$\lim_{x\to-5}\left(\frac{\tan\left(x+5\right)}{x+5}\right)$
$\frac{1}{sinx-1}+\frac{1}{sinx+1}=-2secxtanx$
$x^3+8x^2+15x$
$652+645$
$-6432+536-28$
$x+0+1$
$\left(x^2y^{-4}x^2y^3\right)^2$
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