$x^24x+16$
$\frac{7}{10}x+\frac{1}{2}x$
$\frac{dy}{dt}=\frac{2y\left(1-y\right)}{5}$
$\int x^2\sec^3\left(x^3\right)dx$
$\left|7+9\right|$
$\frac{x}{7}=49$
$6x^2+3x-5=5$
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