$2\left(x+2y\right)^2+\left(-x+2y\right)^2+\left(x+2y\right)\left(x-2y\right)$
$3\cos\left(x\right)+4=0$
$\left(2x-3\right)\left(3x+5\right)$
$9\sec^2x\:-5\tan^2x$
$\sqrt{-52}$
$-13xy^2-26xy+y+2$
$\frac{d}{dx}\left(\sin\left(x^2y\right)+y-4x^3=\cos\left(2x\right)\right)$
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