$\sqrt[7]{ab^2}$
$6 y + 8 > 1.1$
$x^2+9x+19=0$
$\frac{2}{3}x=4$
$\frac{x^6+x^4+x^2+1}{x^2+1}$
$\frac{14x+7}{x^2+x-6}$
$\lim_{x\to-\infty}\left(\frac{x+1}{x^2+3}\right)$
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