$-7x^2-8$
$\frac{5x-5}{x+1}=3$
$10:\:-10\:$
$\left(7ab^3+5x^4\right)^2$
$\frac{\left(x^3-5x^2-30x-18\right)}{\left(x+3\right)}$
$\lim_{x\to\infty}\left(\frac{e^{\left(2x\right)}}{x^4}\right)$
$\left(-2x^2\right)\left(6^3\right)$
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