$\left(x^3+3\right)\left(x^3+8\right)$
$-4+q^4$
$\left(-7x^3\right)\left(2x^5\right)$
$9x^2y+3xy-18xy^2$
$\frac{d^2y}{dx^2}=-3$
$\left(6\right)\left(-4\right)-\left(6\right)\left(-6\right)$
$3x+9>54$
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