$8 x ^ { 3 } + 4 x ^ { 2 } + 2 x - 4$
$\frac{x+8}{3}=\frac{3x-2}{8}$
$45.6\left(2.00\right)$
$-\left|10+\left(-7+5\right)\right|+2$
$\left(x-\frac{1}{10}\right)\left(x+\frac{5}{8}\right)$
$\frac{6}{8x^2-7x}$
$\sec\left(x\right)\sin\left(3x\right)$
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