$\left(12x^2-3x\right)\left(18x-3\right)$
$x^2-3x-5x+6$
$\frac{dy}{dx}=3\left(y+4\right)^2$
$\frac{xy^2dy}{x^2+1}\:=\:\frac{y^3dx}{y+2}$
$\left(cd+2\right)\left(cd-2\right)$
$x2-5x-6\:para\:x=2$
$5\sqrt{8}-7\sqrt{8}$
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