$\int\frac{2x^2+x+7}{\left(2x-1\right)\left(x-1\right)\left(x+3\right)}dx$

$\:\left(\frac{2}{3}x\:-\frac{2}{5}y\right)^2$

$x^3\left(x-2\right)^2\left(x+2\right)^2$

$x^2+8x=c$

$\left(a^{x+1}-2b^{x-1}\right)\left(2b^{x-1}+a^{x+1}\right)^2$

$\left|14\right|$

$8x+\frac{6}{x}$