$\left(2+y\right)\:\frac{dy}{dx}=4+2x$
$\sqrt[3]{\left(4x^3-2x^2+4x\right)}\cdot\left(3x^2-x+1\right)$
$\left(\frac{7}{8}x-5\right)\left(\frac{7}{8}x+5\right)$
$\frac{6^{13}}{6^2}$
$196x^2+28x+1$
$24-7u=3$
$5a^3b^2-8a^2b^3+3ab^4$
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