$\sqrt[4]{6a^2}\sqrt[4]{8a^3}$
$y'=\:2x$
$\frac{d}{dx}\left(x^2y-x^3+y^4-xy+2\right)$
$0-nmg$
$y^{\prime}=\frac{y^{2}}{\sqrt{1-x^{2}}}$
$\frac{dy}{dx}=-y\left(1-y\right)$
$3\sqrt{x}^3-\frac{2}{x^3}+\frac{5}{\sqrt[5]{x^4}}$
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