$\frac{dp}{dt}p-p^2$
$2\frac{1}{3}x^3\left(-\frac{6}{7}y^5\right)$
$\left(2x+3\right)+\left(2y-2\right)\left(\frac{dy}{dx}\right)=0$
$6+8+12$
$5\:-\:10x\:+\:4$
$\left(4x-3\right)\left(x+2\right)$
$\int\:\frac{8x-3}{4x^2-3x+5}dx$
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