$y''\:+\:4\:y'\:+\:13\:y\:=\:0$
$f\left(x\right)=\frac{x^{2}+9}{x^{2}+x-12}$
$\frac{3}{4}\:=\:\frac{1}{4}\:x$
$-3x+4\le4x+5$
$23x+2y^2-z;\:x=2;\:y=10;\:z=1$
$\left(-23\right).\left(-5\right)$
$x^2+16x-8$
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