$y=\frac{1}{2}\sin\left(x\right)-\frac{1}{2}\cos\left(x\right)+10e^{-x}$
$\int_{-1}^2\left(6x\right)dx$
$x^2+10x-56$
$latex:\:\left(5x+1\right)\left(25x^2-5x+1\right)$
$4a^2+12a^3-20a^5$
$\int\left(\frac{5x-21}{x^2-8x+15}\right)dx$
$\frac{64^4}{64^3}$
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