$\frac{x^3-26x-41}{x+4}$
$\left(3m-5n+6\right)+\left(-6m+8-20n\right)+\left(20n+12m-12\right)$
$\int_0^1\left(\frac{5x^5}{\sqrt[3]{2-x^3}}\right)dx$
$\left(-19\right)\left(x+3\right)$
$\int x^3\sqrt{2-x}dx$
$\frac{x^{\frac{5}{2}}}{x^3}$
$x^3+y^3=6$
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