$\sqrt{x^2}+4x-6$
$\left(3y+2\right)^5=\:4x^3-2x\:\:\frac{dy}{dx}=y$
$\lim\:_{g\to\:\infty\:}\left(\frac{3g+2yg^2+y^2g^3}{4-3yg-2y^3g^3}\right)$
$-k^3+2k^2+k-2$
$\int2x^3\left(2x^4+1\right)^3dx$
$\frac{dy}{dx}=\frac{x}{2yx+2y}$
$x^2-18x-7x$
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