$\frac{5+y}{5}+\frac{5+y}{5}$
$\left(a^3-3a^2b+4ab^2\right)\left(a^2b-2ab^2-10b^3\right)$
$4\left(2^2y^3\right)\left(3xy^5\right)$
$\lim_{x\to0}\left(\frac{sec\left(x\right)tan\left(x\right)}{x}\right)$
$7\left(2\right)^2+4\sqrt{\left(2\right)}^2$
$10\geq25-5v$
$-4-x=2x+x-4$
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