$-3tan^2x+1=0$
$b^2-6b+8$
$\frac{dv}{ds}=\frac{s+1}{sv+s}$
$\int_2^{-4}\left(4+x\right)-\left(2-x\right)dx$
$x^2+12x+36=\left(x-6\right)^2$
$x^{-2^4}$
$8m^2+2mn+4mn^2$
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