$\int_0^{12}\left(10t\:e^{-1.01t}\right)dx$

$\int\frac{x^2+2x-6}{\left(x+3\right)^3}dx$

$\left(\frac{1}{3}m^4-\frac{5}{3}n^3\right)^2$

$-6x\le48$

$\tan\left(2\right)x\cdot\cos x+\cos\left(2\right)x=1$

$985-362$

$\sqrt[16]{\left(5\right)\left(13\right)\left(97\right)\left(3^8+2^8\right)+2^{16}}$