$\left(27y^6\right)^{\frac{5}{3}}$
$\frac{64a^3+b^9}{4a+b^3}$
$0x\:\left(-7\right)$
$5x+6-4y-3+3x-2$
$\left(3x-5\right)\left(x+4\right)=x\left(3x-7\right)+8$
$-3-+5\arccos$
$-38-2\cdot7-4\cdot3$
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