$\frac{5}{3}\left(-3\right)$
$\int x^3\sqrt{4x^2-16}dx$
$\lim_{x\to0}\frac{\left(3+x\right)^2-9}{x}$
$x^2=-7$
$t+\frac{1}{t}=\frac{5}{t}$
$\left(-30\right)+25\:x\:6$
$\left(5x^2-3x+40\right)$
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