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$\lim_{x\to\infty}\left(\frac{4x^2+5}{2x+1}\right)$
$\left(\frac{2}{3}x^2y^2-\frac{1}{4}xy^2\right)+\left(\frac{2}{3}x^2y^2-\frac{1}{4}xy^2\right)$
$\left(4c+3+\right)^5$
$\left(xy+y^2\right)\cdot y'=y^2$
$\frac{2a}{a-1}=2+\frac{5}{2a}$
$\left(1-sin^2x\right)tan^2x=sin^2x$
$3x-7\ge17$
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