$\left(4x^{-4}y^8\right)^{-2}$
$\frac{8x^2-64y^3}{2x-4y}$
$\log\left(9-x\right)=\log\left(2x-6\right)$
$x7:x$
$r^2+r-2=0$
$\lim_{x\to4}\left(\left(3\left(x-4\right)\right)^{x-4}\right)$
$\frac{d}{dx}\left(y=4xe^{3x^4}\right)$
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