$\int\left(x^6+\frac{1}{\sqrt{x}}\right)dx$
$\frac{dy}{dx}=\frac{\left(xy\right)}{x^2-y^2}$
$x^3-4x+\frac{7x}{x^2+3}$
$2x-y;x=3;y=-1$
$2x+6y+10x^2+4y+8$
$2a^2+7y\left(2a^2-8y^2\right)$
$-x^2+8x+9$
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