$\frac{dy}{dx}\left(3x-\tan\left(y\right)-4\right)$
$\int\frac{1}{2\left(4u+5\right)}dx$
$525\cdot40$
$2x\frac{dy}{dx}+5xy=0$
$\left(x^{\frac{1}{3}}-\frac{1}{4}x^{-\frac{1}{3}}\right)^2$
$\sqrt{25x}^4y^5$
$\frac{dy}{dx}=\frac{-x-2y}{-4x+y}$
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