$\infty-1.09$
$\left(\:\frac{x^2}{25}+\frac{xy}{5}+\frac{y^2}{4}\right)$
$-12^8$
$\frac{+40}{-8}+5$
$3\left(8c-6\right)+2\left(-2c+5\right)$
$\int\frac{6x^2+14x-3}{x^2\left(x+3\right)}dx$
$\left(-9\right)\left(-2\right)\left(-3\right)\left(-7\right)$
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