$e^{\frac{1}{2}\ln\:\left(x\right)}$
$6m^2n^2,\:9m^2n^2,\:18m^4n^5$
$2x^2+13x+6$
$\left(5x^2+1\right)^2\left(10x\right)$
$\frac { 5 x ^ { 2 } + 6 x - 10 } { x + 1 }$
$\lim_{x\to\infty}\left(x^5e^{-e^2}\right)$
$406\cdot0.015$
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