$\left(a^{-5}\right)^3$

$\left(2a^3+4b^4\right)^2$

$\left(2x-y\right)dx=\left(x-3y\right)dy$

$13x+10+4y+15x$

$\frac{1+\cos\left(x\right)}{\sin\left(x\right)}+\frac{\sin\left(x\right)}{\cos\left(x\right)}=\tan\left(x\right)$

$\frac{2x^4+5x^3-2x^2+4x+8}{2x^2+x-2}$

$\left(3p^2\right)\cdot\left(7pq^2-6pr\right)$