$\left(3x^4y^2+2x^3y^3\right)^3$
$\frac{48}{12}$
$\int\frac{5x-11}{2x^2-x-15}dx$
$2\left(4y-1.9\right)+0.2=9\left(3y-0.4\right)$
$\lim_{x\to3}\left(\frac{2-x}{x-3}\right)$
$\frac{dy}{dx}=\frac{\left(1+2e^y\right)}{x^3e^y}$
$5d^2e^4\left(3-2de^2f\right)$
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