$\lim_{x\to\infty}\left(\frac{1}{x^3}.sin\left(3x+1\right)\right)$
$\frac{d}{dx}x\:cos4x^2$
$\lim_{x\to\frac{1}{2}}\left(\frac{x\cdot cos\left(\pi x\right)}{e^x\cdot\sqrt{e}}\right)$
$x^2dx+4ydy=0$
$\sec x=1.059$
$\frac{x^3+6x-2}{x-5}$
$3x-11>7x+9$
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