$\frac{\cot\left(y\right)-1}{\cot\left(y\right)+1}$
$\int\frac{4x^2+4x-8}{x+2}dx$
$4-\left(-1\right)^2$
$\int\left(2x-8\right)^2dx$
$\frac{b}{6}-1>1$
$\left(xy^2-4x^2y^3+4x^2\right).\left(-2x^3y\right)$
$2x\:-\:5y\:=\:-7\:$
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