$2x^2\:-4$

$\int\left(\frac{1}{9x+2}\right)dx$

$\left(2p+3\right)\left(3p+1\right)$

$\lim\:_{x\to\:\infty}\left(\frac{2x^4-3x^2+1}{1x^5+2x^3+6x}\right)$

$\frac{\left(5m^3+3n^3\right)\left(56m^4-4n^4\right)}{8m^2n^5}$

$2\left(t-2\right)+2=2\left(2t-5\right)$

$49x^2-98x+49$