$\frac{1}{3}\cdot\ln\left(3e^x+e^6-3\right)$
$\lim_{x\to\infty}\left(\frac{\left(2+x\right)^3-8}{x}\right)$
$\frac{du}{dx}=-0.1x$
$\left(1+2y\right)dx=\left(x^2-4\right)dy$
$\left(5m^4-b^3\right)^3$
$a^3-27b^3$
$\frac{3x^2y^2}{-7x^3y^3\cdot5x^2y^2}$
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