$4x\:+\:7y\:-\:4x\:-\:8y$
$\int20x^3\left(5x^4+3\right)^{-3}dx$
$27\cdot1$
$4x-4=44$
$\frac{x^3-5x^2+6x-5}{x+1}$
$\left(8x\:+\:y^2\right)^3$
$\sec\left(x\right)^4+\sec\left(x\right)^2\tan\left(x\right)-2\tan\left(x\right)^4$
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