$x^2\left(\frac{\left(108-x^2\right)}{4}\right)$
$8x+4>4x+12$
$y+8=18$
$\int_{-\infty\:}^0\:xe^{4x^2-1}dx$
$6\left(8x+3\right)=-22+8x$
$0,345-0,6+2,0$
$\ \sqrt{81a^7b^{12}c^9}$
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