$\frac{\left(x+7\right)}{4}+1<\frac{\left(3x-2\right)}{x+4}$
$-3y+7x-2+3x-2y-1$
$2\ln\left(x\right)+3\ln\left(y\right)-\ln\left(4\right)$
$xydx=\left(y^2-xy+x^2\right)dx$
$9m^2-36m+36$
$40+x=25$
$3\left(5xy\right)^2$
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