$\int\frac{7\sqrt{x^2-25}}{x^4}dx$
$du=\left(\frac{x}{\sqrt{4+x^2}}\right)dx$
$-7x^2+2x+3$
$2\:x\:7\:+\:2\:x\:6\:+\:2\:x\:2\:+\:2\:x\:9$
$\left(6j+2\right)-\left(-5j+5\right)$
$x-20\cdot x-25$
$\frac{x^2-5x+6}{x-2}=\frac{x}{x-9}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!