$\left(x-y\right)^2+4\left(x-y\right)z+4z^2$
$3+\ln\left(x-3\right)=2$
$\left(b\right)-9^2$
$-0.63x+0.33x=7.2$
$4\:sec^2-7\:tan^2x=3$
$\frac{2x-1}{3}+2>\frac{x+1}{4}$
$\frac{dy}{dx}x^{5y}=y^{8x}$
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